JAWABAN TUGAS SUBNETING

  

     1.   C (255.255.254.0)

IIIIIIII.IIIIIII.IIIIIII0.00000000

2. A (address ; 192.168.1.14, gateway; 192.168.1.33)

C (address ; 192.168.1.32, gateway; 192.168.1.33)

3.A (172.31.192.166 = I0I0II00.000IIIII.II000000.I0I00II0)

(255.255.255.248 = IIIIIIII.IIIIIIII.IIIIIIII.IIII000)

(172.31.192.160= I0I0II00.000IIIII.II000000.I0I00000)

4.E ( 255.255.252.0 = IIIIIII.IIIIIIII.IIIIII00.0000000)

D ( 255.255.0.0 = IIIIIIII.IIIIIIII.000000000.00000000)

5.C ( 172.16.128.0 And 255.255.192.0)

6.D ( Subnetwork address)

7.C (30 network/ 6 host)

[ 192.168.99.0 = II00000.I0I0I000.0II000II.00000000]

[ 255.255.255.248 = IIIIIII.IIIIIIII.IIIIIIII.IIIII000]

[SN: 2⁵-2= 30

[NA: 2³-2= 6

8.C ( 30) [255.255.255.224.0 = IIIIIIII.IIIIIIII.IIIIIIII.III00000] SM: 2³=8 NA: 2⁵-2= 30

9.C (255.255.255.224) SM: 2³=8 NA: 2⁵-2= 30

10.B ( 255.255.255.240) [IIIIIIII.IIIIIIII.IIIIIIII.IIII0000] SM: 2⁴=16 NA: 2⁴-2=14

11.E ( 255.255.255.128) [IIIIIIII.IIIIIIII.IIIIIIII.I0000000] SM: 2⁹=512 NA: 2⁷-2= 126

12.C ( 172.32.0.0)

[172.32.65.13 = I0I0II00.00I00000.0I00000I.0000II0I]

[255.255.0.0 = IIIIIIII.IIIIIIII.00000000.00000000]

[172.32.0.0 = I0I0II00.00I00000.00000000.0000000]

14. A (115.64.8.31)

C (115.64.6.255)

F (155.64.12.128)

15. C ( 200.10.5.0)

[200.10.5.68/28=II00I000.0000I0I0.00000I0I.0I000I00]

[255.255.255.240=IIIIIIII.IIIIIIII.IIIIIIII.IIII0000]

[200.10.5.0 =II00I000.0000I0I0.00000I0I.00000000]

16. E ( 8 Subnet, 2046 host each)

[SM:2³=8

[NA:2¹¹-2=2046